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Constants Part A A 5.00-F capacitor that is initially uncharged is connected in series with a 5.00-Ω resistor and an emf sour

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Answer #1

Power, P = I^2 R = 300 W

I^2 x 5 = 300

Current, I = 7.75 A

Voltage, Vc = 70 - (7.75 x 5) = 31.27 V

Energy, E = 0.5 CV^2 = 0.5 x 5 x 10^-6 x 31.27^2

E = 2.44 x 10^-3 J

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