Question

Write a function named midvalue that is passed three unique int values and returns the one that is in the middle. Thus, midvalue(5,28,14) returns 14. ( in c++)

Answer 1

Here I am providing the answer for the above question:

Code:

#include <bits/stdc++.h>
using namespace std;
  
int midvalue(int , int , int ); //funtion declaration
  
int main()
{
cout <<"midvalue:"<<midvalue(5,28,14);  
return 0;
}

int midvalue(int x, int y, int z)
{
//if y is greater than x and less then z (or) y is greater than z and less than x
if ((x < y && y < z) || (z < y && y < x))
return y;
//if x is greater than y and less then z (or) x is greater than z and less than y
else if ((y < x && x < z) || (z < x && x < y))
return x;
else
return z;
}
Screenshot of code:

#include <bits/stdc++.h> using namespace std; int midvalue(int , int , int ); int main() cout <<"midvalue:"<<midvalue(5,28,14); return 0; int midvalue(int x, int y, int z), //if y is greater than x and less then z (or) y is greater than z and less than xi if ((x < y && y < z) || (z < y && y < x)), return y; //if x is greater than y and less then z (or) x is greater than z and less than y else if ((y < x && x <_z) || (z < x && x < y)) return x; else return z;

Output:

midvalue:14

Hoping that the above answer will help you...Thank you...