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Can you please check this ICE table to see if I am correct? He requires an ICE table but if someone can check it for me I would appreciate it...

2. Solve an equilibrium problem (using an ICE table) to calculate the pH of a solution that is 0.20 M in HCHO2 and 0.15 M in NaCHO2? Ka 1.8 x 10-4 ICE H+ HCHO2 0.20 CHO2 0.15 +X 0.15+ x +X 0.20-x (0.15+x)(x) 0.00018 0.20 -x 0.00018 (0.20 - x)- (0.15 + x) (x) 0.000036-0.00018x 0.15x + x2 0.15x + x2-0.000036 + 0.000 18x = 0 (x2) + (0.15018 x)-0.0000362 0 0.15018 ± v0.150182-4(1)(-0.000036) x = 0.000479 / 2-0.000240-x 0.15-0.000240-0.15 M = [HCHO2] 0.15 + 0.000240 = 0.15 M [CH02] 2.40 x 104- [H+] pH- - log (0.000240) 3.62

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