Question

/*Write a Java program that generates 1000 random integers, * calculates the average and prints two counts, one for the * numbers lower than the average and one for the numbers larger than the average. */

Use java thanks

Answer 1

SOURCE CODE IN JAVA:

import java.util.Random;
class RandomNumbers
{
public static void main(String args[])
{
Random r=new Random(); //creating object of Random class to use nextInt() to generate integers
final int BOUND=1000; //random integers will be in the range 0 to BOUND
int arr[]=new int[1000]; //creating empty array of size 1000
double sum=0; //to store sum of elements
for(int i=0;i<1000;i++) //filling the array and calculating the sum of elements
{
arr[i]=r.nextInt(BOUND+1);
sum+=arr[i];
}
double avg=sum/1000; //calculating average of elements
int above=0,below=0; //to store two counts, above average and below average
for(int i=0;i<1000;i++) //counting above average and below average
{
if(arr[i]>avg)
above++;
else if(arr[i]<avg)
below++;
}
//output
System.out.println(avg+" is the average");
System.out.println(above+" numbers were above average");
System.out.println(below+" numbers were below average");
}
}

OUTPUT:

2 Blue): Terminal Window - Chegg Options 478.61 is the average 483 numbers were above average 517 numbers were below average