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Q.5 The first order degradation rate of a drug at 80°C and 70 °C are 0.0073 hr and 0.0054 hr respectively. What is the shelf-

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Answer #1

Using the combined arrhenius equation, the activation energy of the reaction is determined:

ln (k2 / k1) = Ea / R * (1 / T1 - 1 / T2)

ln (0.0054 / 0.0073) = Ea / 0.008314 * (1/353 - 1/343)

Ea = 30.35 kJ / mol is cleared

Using the same equation, the constant k is determined for 25 and 6 ° C:

ln (k3 / 0.0073) = 30.35 / 0.008314 * (1/353 - 1/298)

It clears k3 = 0.0011 h-1

k4 = 0.0005 h-1

The shelf-time is calculated:

t1 / 2 3 = ln2 / k3 = ln 2 / 0.0011 = 630 h

t1 / 2 4 = ln2 / 0.0005 = 1385 h

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