Question

T&content_id=8 Downward, Left (Q3) Downward, Right (Q4) QUESTION 4 125 kN HRV īT HRV 453 6 m G RCH = 125 kN Rcv = 96.43 kN Аг 6 m - 8 m Rav = 3.57 kN h00 kn The force in Member CB is [CBForce). (Answer Numeric Only!) QUESTION 5 - 125 KN

Answer 1

SO] → 125 EN 6m 125 kN & - BT . 3.57KN 100 ogbo 43 KN h 8m lom 6m Lo 8m at Joint co- sino = 6/10 ceso= 8/10 FED 004 125 kN 96.34 KN Fy=0, FCD sino +9 6034=0 FCD X 6 =-96.34 10 Cambrie - FCB +Focoso +125 =0 FCB - 160.56688 lo +125 =0 I Fee = 3.453) KN . Answer: (t) Tensile