Question

A Review | Constants Pen Ethanol has a heat of vaporization of 38.56 kJ/mol and a normal boiling point of 78.4 °C. Part A You may want to reference (Pages 478 - 487) Section 11.5 while completing this problem. What is the vapor pressure of ethanol at 19°C? Express your answer using two significant figures. Ivo A¢ * * O O ? P= 2.4•10-2 torr Submit Previous Answers Request Answer X Incorrect; Try Again; 13 attempts remaining Provide Feedback

Answer 1

According clausius - clapeyron equation → AH vap loro beat ta] P, = inital pressure at boiling = 1 atm point P2 = ? (Final pressure) 38.56 kJ /mol = 38.56X1033 /mof A Hvap: T2 = Final temperature = 19°C = 273 +19 = 292k Ti = Intial temperature = 35104 K R = 8.314 J/molok

AHv > me: [ 1] * RL 2423514|| 11AM, 38.56 x 10°alual (5,388x volt) 2.34 TwiftK > low.2.684 In P. -- 2.684 aft > F. : 0.063 2 of P2 = 0.0682 X 760 torn litatum= .700 for | = 51.85 Hown | * ? :- vapour pressure at lade is 51.855 torr