Question

In the region shown in the image, there is a uniform electric field of magnitude 52.5 N/C which points in the positive y-direction. Points 2, 3, and 4 are all 0.497 m away from point 1, and the angle o = 46.4". Calculate the potential differences AV between each indicated pair of points. V2 - V1 = 26.09 V- Vi = 0 Va-V1 = 18.90 12-V= -44.99

Answer 1

we have the relation E = -dv - dv=-Ede. joining points, and Ofor V₂-vi No field along line 2 so that V₂ -V,=0 - For V3-vi field is along y axus is 52.5 NIG de =-0.497 m. dv=v₂-V, =-E.de 5.52.5x60.497) = +26-1 Nm/c 6 for VG- , , de=0.497 cos 46.4 de=-0.343 m Conly y co-ordinate Needed) dv=Vu-V,= E.de --52.5x(0:343) = +18.01 Nmic

simillarly Ve-V4 =-18.1 Non As only y component is considered because E is along y anas. so dv between point (2,6) is same as point (1,4) . but de is qve. so do is aive for (V₂-vu)..