from above :joint distribution of X and Y is as follows:
a)
| x | ||||
| y | 1 | 2 | 3 | Total |
| 1 | 0.0500 | 0.0500 | 0.1000 | 0.2000 |
| 3 | 0.0500 | 0.1000 | 0.3500 | 0.5000 |
| 5 | 0.0000 | 0.2000 | 0.1000 | 0.3000 |
| Total | 0.1000 | 0.3500 | 0.5500 | 1.0000 |
a)
from above marginal distribution of X is as follows:
| x | P(x) |
| 1 | 0.1000 |
| 2 | 0.3500 |
| 3 | 0.5500 |
b)
marginal distribution of Y is as follows:\
| y | P(y) |
| 1 | 0.2000 |
| 3 | 0.5000 |
| 5 | 0.3000 |
c)P(Y=3|X=2)=P(X=2;Y=3)/P(X=2)=0.1/0.35=2/7
d)
here as P(X=1;Y=1)=0.05 ; while P(X=1)*P(Y=1)=0.1*0.2=0.02
as they both are not equal ; hence X and Y are not independent,
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Let X denote the number of
times (1, 2, or 3 times) a certain machine malfunctions on any
given day.
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