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P2. (50p) A 100 kVA, 400 V synchronous machine has the following equivalent circuit parameters: X, = 2.0.2, R = 0.25 12, PART
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Solution Given a Synchronous machine rated look VA, 4000 Sydhetsensus X (=2r, Re=0.25 Part 1) Given machine works as. Rs jxqCat - - Itan ( Clan ) Clan 2 0.25 82.87° cos(Osto -Ist z Vt =-72.17X 2.015 2x 400 √3 coslost 8) = -0.314 cost [-0.314) 82.87+calculating 6: - cal EJ = Vt Lo + Is L&* [Rstjxz] 400 at 72.17L25.481 x2.0154 (82.87° √3 4004 145.42 (108-711 √3 23094 + (46614 load = full verload with 0.9 leading Power Lector S= look va 3 ray Is = 100x10 Te 100x10} = 144.34A √3x 400 costa 0.9 %) 2- phasor diagram Tats ES 8= 63.44° Mats Dash 250ml Is Rs to lo part ② Machine aurs motor with I= 1440 Power factor 1, (aco =)pharos t. Is fa 8=-55.904 Texs Xs a as Ef = Vt LO I E cos$= 0.6 XI = 144A (-36.86 4- 36.86, Lagging 1s (estjxs) 400 144 L-36.f line = 210-785x83 O 365.077 8 = -81.97 phasor Is fa • Lo 36.86 Ist 1 81.97 ç Cosp=0.8 b= 36.86° leading Is=144 L36.86 2) Ephasor 36.86 33.9° L -IPs Tas

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