Question

1) When 1336 J1336 J of heat energy is added to 47.6 g47.6 g of hexane, C6H14,C6H14, the temperature increases by 12.4 ∘C.12.4 ∘C.

Calculate the molar heat capacity of C6H14.

2) Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 9.20 MJ9.20 MJ of energy in the form of heat if the temperature of the sodium is not to increase by more than 10.0 °C?10.0 °C? Use CP=30.8 J/(K⋅mol)CP=30.8 J/(K⋅mol) for Na(l)Na(l) at 500 K.

3) A researcher studying the nutritional value of a new candy places a 4.10 g4.10 g sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.56 ∘C.2.56 ∘C. If the heat capacity of the calorimeter is 30.20 kJ⋅K−1,30.20 kJ⋅K−1, how many nutritional Calories are there per gram of the candy?

Answer 1

1 number of moles of hexane = 47.6 g 86 g/mol 0.55 mol = DT = 12.4°C. q- 13365 q= neat. Molar heat capacity, eaq ПАТ 1336(0) 0-55 mol x12.46 195.89 I moltoct. =