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Q1. [4+2+4 marks] Consider the following joint probability distribution fxy(x, y). 2 4 0.05 0.1 0,05 0.02 0.1 0.05 2 0.02 0.1
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Solution Given joint pvobability distribucti on fy (). K 3 2 O.OS L4 O-O2 o- O o-45 3 27 O-13 O-02 1 O- 15 O18 b.이 O.55 O35 CE(XY) 5-57 Urt pb o dete (Vxo.1) 2x35) (3x0-55) odl O-7 4 10665 udo 2 45 E (X 2-45 doibuloc doituietil yHilidedorg yfy (Y ECYVCX) ECX2) (035)(x0-ss) ECx2) 14t 4.9s 6-4S v(x) 6-4S-(2-45) 6.45 -6.00 14 O.4S v(x) o45 v x) v(A) Fhope this will help you

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