Question

A current carrying circular wire has a radius of 4.0 cm. This circular wire placed in a magnetic field of 4.8 mt. If the current is 3.4 A, calculate the maximum torque. 5 Am 12.1 a. T Select one: 4.2x10 b. 2.2x10 A. m2.1 C.8.2x10 Am d. 6.2x10. m2.1 2 T

Answer 1

Soluchon we must Know B = Torque on a loop of wire is Juien by T= mB sino where ma mognetic moment of loop magnett field in which loop is present Angle bw m & B For maximum torque O = 90' do that sino = sin 90°= 1 (woximem alue of sine function] Hence the aceranio is Now 31 tol B A 0.04 m 0.0171 Now, m=iA where is current in loup = 3.4A Area of loop = ter² & Hodies = 81 = 4cm = m=iA 3.4 X TTX (0.04) 2 4.8mT 4.8x103T T= mB singo = mB = 0.0171 X 4.8 X10-3 (maximum) IT = 8.2 x 10 & Bs 5 Am²T Hope you like my solution 4 my efforts.)