Question

Sec 3, Question 3.27 Compute the mean, the median, and the mode for the following data. Class 0-under 2 2-under 4 4-under 6 6-under 8 8-under 10 10-under 12 12-under 14 *Round your answer to 2 decimal places. Mean = Median = Mode =

Answer 1

PageNoo Saution Given data 37 29 16 Clan o-under-2 2- under4 T 4 under 6 6 under 8 8 under 10 10 under 128 12 underly 10 To find 3 Mean 6 Median Mode. + Mean class 0-2 Midvalle opis | ti | tiri 37 37 29 87 2-4 14-6 Here, Midvalle is upper limit toner line 80 2 2 105 for 16-8 8-10 10-12 90 EX!= 042 --1 88 112-14 - 78 12565

Pegemea 01 Mean tot uz • 565 : 4.6694 Mean : 4.667 → Median we know that, median ft N/a acfxh بالا و sh: cou width Ź N : Total frequency sl ower burday of the median aau. 04 Les tran cummuildive frequency. sf = frequency of Medion Clay clan t i fi I Ler than formulative frequenyt ce T 37 37 4N12 31129=66 In Medion 4-6 66 + 16 = 82 6-2 15 82 +15.97 97 to 107 T10-12 o 10++8 -05 IS +€ 121 EN 0.0 ca.

Paginn → N Nils malla 60-5 1:29, , ef - 37 ha 2 i N101, . Median = d+w/2-cif xh = • = . Go.5-37 -Y2 29 2+ 0.8103X2) 2+ 1.6206 3.6206 = 3.62 Median → Mode ule know that, . formula for mode alt tm-fi xh O atm finde where d= cover boundary of modleast fm frequency of model clan. fp = frequeny or port model class ti : frequency of pre model clan h = width of model class

ca ruontent 29. 4-6 16 6-8 10 10-12 12-14 Model 0.2 clan is Then, fm = 37 dino fr = 29 h =2 Mode = It fm ti xh r , • O H 37 - 0 72 2134) -0-29 3 , - 74-29 X2 = 0.822 X 2 1.644 Mean = modian - Modi , 4.66 3.62 Mode = 1.64 ]