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Solid ammonium phosphate is slowly added to 50.0 mL of a 0.0482 M barium nitrate solution. The concentration of phosphate ion
Solid potassium chromate is slowly added to 125 mL of a 0.0485 M barium acetate solution. The concentration of chromate ion r
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Answer #1

We need to find [PO43-] such that Ksp of Barium Phosphate = [Ba2+]3 * [PO43-]2

3.4 * 10-23 = 0.04823 * [PO43-]2

SOlving, [PO43-]= 3.04 * 10-9 M

We need to find [CrO42-] so that: Ksp = [Ba2+] * [CrO42-]

1.2 * 10-10 = 0.0485 * [CrO42-]

SOlving, [CrO42-] = 2.47 * 10-9 M

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