Question

calculate the [OH-] when the [H3O+] has the following values.

4. Calculate the [OH-] when the [H3O+] has the following values: a. [H3O+]= 1x 10-3M= b. [H3O+]= 1x 10-10 M c. [H3O+]= 1x 10-6 M d. [H30*)= 2.8 x 10-13 M

complete the following table.

Answer 1

Solutions ч. а) (но*) = 1 х 10 м Сно+) (он)= 1x1019 Гон-) [но*) 1x 10-19 Therefore, Сон-] = 1x 10-14 1 х 10-3 10-19 x 10 [он-) (он-] 103 1x Jo-" м Aug » Гңot] = 1х10-10 м low-] 1x 10-14 1 x D-lo [он) E 1 х 10-ч M Answer 3 [но+) = 1х10-6 м (он) 1х10-19 1 х 10-6 Сон-J 1 x 10 M Ho4

ed [hot] 28.8 x 1013 M Cor] Ix 10-14 2.8 x 10-13 COH) 0.357 x 10-) COH-] = 3.57 x 10-2 M Answey (e) (440+] = 8.6 x 10-7 M Com] | x 10-14 8.6 x 10-7 [OH-] = 0.116 x 10-7 [OH-] 1•16 x 10-8 M Auswer Ist Row (40+) = 1 * 10-8 M [OH-] = 1x 10-14 1x10-8 COH) = 1 x 10-6 M Answer pH - dog [H3O+] - log 1x 188 - (logi + (8) logio) -10-8x1) And wer (Basic) IT PH = 8

0.001 and Row & [440+) COH-] 1x10-14 O/001 [on-] 1x10-14X 1000 [OH-] = 1 x 10" M Answer PH ph - log [bot] -log ix 10-3 = (140*) - 0.001 (140+)= 1x10-3M - Glog) + (-3) deg o) -(0-3x1) (Acidic) - PH 3 Answer I nd Row :- (OH-] = { x 10-5 [Hot] 1x10-14 COH) Ix 10-14 2x10-5 0.5X10-9 = = 5.0 x 10-10 M Answer

put a log [got] -dog 5 x 10-10 -(dog 5 + log 100) -(log 5 + (-10) logio) :-(0.69897 –10x1) =-(-9.36103) pH Answer (Basic) 9.3 th TV Row - | x 10-14 [oH-] = 1 x 10te M [Hot] 1x 10-12 (H40] 1x10-2 M Answer pH = -log (H₂ot PH - log 1x100 + log -(dog! 10) E-(0+(-2)x1) :-(-2) (Acidic) PH Answer

Ith Row :- 10- PA pH = to (но* ) (но1] Сң,6*] 10-10 1х10-10 м AuuseЯ (он-] (х 10-14 1x 10-10 (он-) 1х10-4 Auswer (Basic ч" Row :- [ңot] = 5x1-8 M (он-) 1 х 10-19 гх 10-8 [онг] = О. 2 x To 10-6 Сон-) 2.6 x ID-* М Answer Рң PH = - Зоя Сң0*] — Моя 5 x 10: 8 + •я 0-8) -(dog 5 -(dog в +(-8) Spg ") = -(o-6 904+ - вхі) = - (- +-зо1оз) Ausway (Basic) = 4.3

with Row :- Neutral solution ,طر 10^PH pH = 7 Answer (40+) (120+] H0+) = 1x 10-7 M Answer [OH-] 1*10-7 107 1 x 10-14 [OH-] 1x 10-7 M Answer Virth 'Row - pH = 1 10-PH CH, 0] CH20+] = (H20+] - 10-1 1*10-'M Auswer COH-] = 1x10-14 1x10-1 - 13 [OH-] - 1*100 Answer (Acidic)