A dice game is played with two distinct 12 sided dice. It costs $3 to roll...

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math Statistics-And-Probability

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Sum of 13 is got with probability ?

{12,1}*2
{11,2}*2
{10,3}*2
{9,4}*2
{8,5}*2
{7,6}*2 = 12 ways

{11 or 15}
11 - {10,1}*2
{9,2}*2
{8,3}*2
{7,4}*2
{6,5}*2
=10 ways

15 - {12,3}*2
{11,4}*2
{10,5}*2
{9,6}*2
{8,7}*2
=10 ways

Sum of 7
{6,1}*2
{5,2}*2
{4,3}*2
=6 ways

Sum of 9
{6,3}*2
{7,2}*2
{8,1}*2
{4,5}*2
=8 ways

Sum of 17
{12,5}*2
{11,6}*2
{10,7}*2
{9,8}*2 = 8 ways

Sum of 19
{12,7}*2
{11,8}*2
{10,9}*2
= 6 ways

= 6+8+8+6 = 28 ways

Total kind of dice plays =12*12 = 144

Expected value = (12/144)*10 + (10+10)*6/144 + (28*3/144) - $3
= -$0.75

So, expected value is a loss of 75 cents or a loss of $.75

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Answer 2

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