Homework Answers
Answer:
Given reaction is
P4(g) + 5O2(g) <-------> P4O10(s)
Kp=1/[P(P4(g))] x [P(O2(g))]^5
Here P4O10(s) is pure solid, therefore it doesn't participate in Kp expression.
Given P(P4(g))=0.52 atm, P(O2(g))=(2.1x10^-3) atm
Kp=1/(0.52) x (2.1x10^-3)^5
Kp=4.7 x 10^13
Since ∆G=- RT lnKp
Where R=8.314 J/mol K, T=temperature = 600 K.
∆G=-(8.314 J/mol.K x 600 K) ln(4.7x10^13)
∆G=-157049.88 J/mol
∆G=157.05 kJ/mol. (Since 1kJ=1000 J).
Please let me know if you have any doubt. Thank you
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