Question

V max 10 m/s h 5,2 m h max How far can the football go if it can't touch the roof and the output speed at it biggest is v max.

Answer 1

0 Pr Vmax = 10 m/s h = 5m Vmax S 닝 h = am To final Max dist it can travel without touching the Roof Sop Case- Elomils behers Vmad h = 5 / Vmax 20:45 Conditions to cover maa distaose is that projectile or launch should be 45° to Horizontal. Vmed Vman sin45 0:45 Vman Cosas Vman Cos45 Horizontal componest of velocity Vman &in 45 - Vertical composeest of Velowing

Max for distance (or) Required horizontal listaxe conced >> Horizonteel Corporat X time of relocity > Vroom cos 45 x 1.44 16 sec tates > 10X.C0145 x 1.44116 17 10.19365 meter Case-2 when Imac & 10m/s he am ha 2 rooned. . ble know that for man horizontal dist the angle with horizontal should be 45 freom Previous Case iee Case 1 Vertical dist travelled del Men height reached I V fino x 2

V sin45 I fit 7 eg of Motin, Initieel velocity on vertical component Veno v=ut at 14 eg of Mottoos. Appling He Can birité V Hin 45= 10 $7445 Final velocity = ola Olas it stops at top) acceration -g peeting above in Equation 0 = losin45-9(4) lo sth45. lokin45 ta oo 9.81 t = 0.7208 sec this time is takes to reach at max height, So toteal time will be double because time to go up t time to come down and equal. both will be fo Total time taken=1.44 16 sec

☺ →lox 645X0.7204 = 5.0968m blich is greater than '2' so it will touch the roof so Assuming it is profected at an angle 0. & Vmad Vimano Vm como Here the condition to Mar Height can be am. So applying the conclities, V 242, 2005 eg of 3rd eg of motia fino OF (10 802)2+249.81% 2

. to sho=J 2x 2 x 9.81 sino = 0.626418 0 - 36.78636 - Coso =0.77948 > 1 st Tirone takes to reach the top Naudat Saop of Mon 0 = 10 85o-gt ION O. 626418 0.63855 9.8 Total time takes will be twice this time = 2+ = 1.2771sec => Max far dist or Maxthon Zostal dist traveled - VX COLO x 1.2771 10X0.77946x1.277 9.954746 m of 2