Question

By using appropriate examples, apply your knowledge in solid mechanics to explain about a. Statically indeterminate axially loaded member b. Statically indeterminate torsional member. C Statically determinate bent member d. Statically determinate shear loaded member Your explanation must contain related description, equation, and figure.

CAN SOMEONE DO IT ON C AND D because need understanding (hope you can explain it well)

Answer 1

Ang (a) statically indeterm a statically indeterminate axially Loaded Statically indeterminate member can be defined as when the Number of unknown is more than the number of equation's Expt fixed enas (both) of bar - A. SB RARA EL To Be K Rc 22 14 Where Pais Axially load Step- ] introduce Reactions Red RA Retra =P - Here Number of reaction is one 4 unknown are two so that this chove member is atially interminate member. L- for solving this compatibelity eqpouquired, Stoke = dit de chotel ao i both ends are fired dited = 0 - 0 8 =-62

are know. مدل AE So for member 4 d. – P. da- Po 22 ARE2 Put there da do values in ear a P,4 – P2 22 Ak Assume crossection Area are is same a same material P. L = – Pg 22 - ③ P. 4 P2 lood on member & B P=RA , P = – Re (comp. ) Step-3 RAL, = – (-Ralla Assume RAL, & Reha Assume ( = 24) RAK = Rex 24 RA - The – Put in can 3 Re - P R= % & RA=29/3

Ary-b statically statica indeterminate torsien member s at both the ends with member tired torsion (T). Fat TL 2L - introduction of reactiboss at fired and (i) c.w.d(tre) c.c.win (-ve) TA & Ti=-TA Te T2 =- or Te -- TATT (ii) (ii) Tatte = T - civl Ototel = Q +0,00 0 ( became it is fired) compartibacity en . Ta Lz G Jp = and ag Tixx =- Tq x 24 - = - (- TA +1)x2 -TA = 2TA - 27 3TA = 27 =) TA= 27 from ear Te = 3 mo

Ansrc T statically determinate bent membert d etatically diterme a statically determinate member, when Number of equation = Number of unknown exp- Simply Supported beam cantilever beam apported beam Now we considera RA for equilibrium. Emzo - EH=o, {v=o Ev=0 RA+RB= w -0 Em: Ô taking moment about all aw x2 - RB X 32 = 0 a RB = 231 ao sron en Ro =

Ansed statically a t Statically determinate Shear Weded manter One free ended her with torsion (T) is Statically determinate shear looded member- eto- Ad, GG = pd Ad P o & Torsion Angulastwist shear soogle equation & F - GOO Ty torsion (Peristing) rem shear stren. G modules of Pigidity shear strain. (r) for Rol