Homework Answers
Given that
energy U=50*10^-12 J
volume V=64 cm
basing on the concept of electrostatices
now we find the electric field
electric field E=[2U/
V]^1/2
=[2*50*10^-12/8.85*10^-12*64*10^-6]^1/2
=0.4202*10^3
=420.2 V/m
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150 pJ of energy is stored in a 1.0 cm times 1.0 cm times 1.0 cm region of uniform electric field
150 pJ of energy is stored in a 1.0 cm times 1.0 cm times 1.0 cm region of uniform electric field. What is the electric field strength?
60.0 pJ of energy is stored in a 2.00 cm × 2.00 cm × 2.00 cm...
60.0 pJ of energy is stored in a 2.00 cm × 2.00 cm × 2.00 cm region of uniform electric field. What is the electric field strength?
10.0 pJ of energy is stored in a 3.00 cm × 3.00 cm × 3.00 cm...
10.0 pJ of energy is stored in a 3.00 cm × 3.00 cm × 3.00 cm region of uniform electric field. What is the electric field strength?
30.0 p. J of energy is stored in a 1.50 cm times 1.50 cm times 1.50...
30.0 p. J of energy is stored in a 1.50 cm times 1.50 cm times 1.50 cm region of uniform electric field. What is the electric field strength? Express your answer with the appropriate units.
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