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(1 point) Starting from the point (4,3,2)(4,3,2) reparametrize the curve r(t)=(4+3t)i+(3−3t)j+(2−2t)kr(t)=(4+3t)i+(3−3t)j+(2−2t)k in terms of arclength.
Find L 2s+4 s(s2+4) 5 -3t (write 5/6 by 5 e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)).
The Laplace transform of the following time function f (t) = 2t2 + e-2t sin 3t is
Please substitute cos 3t with cos 2t instead. Thank you
Transformations at Work Solve the IVPs in Problem using Laplace transforms. y" + y = cos 3t; y(0) = 1, y'(0) = -||
2t +1 if 0 <t< 2 Consider f(t) = { | 3t if t > 2. (a) Use the table of Laplace transforms directly to find the Laplace transform of f. (b) Express f in terms of the unit step function, then use Theorem 6.3.1 to find the Laplace transform of f.
45 Find L 32 +25-3 5 -3t (write 5/6 by 6' , e^{-3t} by e and sin(2t) or cos(3t) by sin(2t) or cos(3t)). **{3+2-3)
3.12. Determine the exponential Fourier series for the following periodic signals: sin 2t + sin 3t (a) x(t) = 2 sint (b) x(t)-Σ δ(t-kT) k-00
4) Do the lines: L: x = 2t + 3, y = 3t – 2, z = 4t - 1 and L2 : x = 8 +6, y = 2s + 2, z = 2s + 5 intersect? If not provide a reason, if yes find the intersection point.
Find the general solution x(t) of: x'' + 4x = 3 cos(2t) + 4 cos(3t) using the method of undetermined coefficients.
Find the curvature of r(t) = (-7 sin(t), cos(2t), –3t) at t = ž. (Use symbolic notation and fractions where needed.) k () =