Assume that round widgets from a manufacturing process have diameters that are normally distributed with mean 135.75 centimeters and standard deviation 1.85 centimeters. The chances that a randomly selected widget has diameter between 129 centimeters and 143 centimeters is closest to which of the following?
a. 99,999 out of 100,000
b. 99 out of 100
c. 999 out of 1,000
d. 9,999 out of 10,000

Assume that round widgets from a manufacturing process have diameters that are normally distributed with mean...
Assume that round widgets from a manufacturing process have diameters that are normally distributed with mean 150.55 centimeters and standard deviation 1.68 centimeters. The chances that a randomly selected widget has diameter greater than 156.5 centimeters is closest to which of the following? O a. 1 out of 500 O b. 1 out of 10,000 O c. 1 out of 5,000 O d. 1 out of 1,000
Assume that round widgets from a manufacturing process have diameters that are normally distributed with mean 150.55 centimeters and standard deviation 1.68 centimeters. The chances that a randomly selected widget has diameter greater than 156.5 centimeters is closest to which of the following?
A) The diameters of pencils produced by a certain machine are normally distributed with a mean of 0.30 inches and a standard deviation of 0.01 inches. What is the probability that the diameter of a randomly selected pencil will be between 0.21 and 0.29 inches? B) The diameters of pencils produced by a certain machine are normally distributed with a mean of 0.30 inches and a standard deviation of 0.01 inches. What is the probability that the diameter of a...
The diameters of ball bearings are distributed normally. The mean diameter is 99 millimeters and the standard deviation is 5 millimeters. Find the probability that the diameter of a selected bearing is greater than 109 millimeters. Round your answer to four decimal places.
Precision manufacturing: A process manufactures ball bearings with diameters that are normally distributed with mean 25.2 millimeters and standard deviation 0.07 millimeter. Round the answers to at least four decimal places. (a) Find the 20 percentile of the diameters. (b) Find the 34th percentile of the diameters. (c) A hole is to be designed so that 1% of the ball bearings will fit through it. The bearings that fit through the hole will be melted down and remade. What should...
The diameters of ball bearings are distributed normally. The mean diameter is 74 millimeters and the standard deviation is 3 millimeters. Find the probability that the diameter of a selected bearing is greater than 71 millimeters. Round your answer to four decimal places.
The diameters of ball bearings are distributed normally. The mean diameter is 96 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 105 millimeters. Round your answer to four decimal places.
The diameters of ball bearings are distributed normally. The mean diameter is 145 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 134 millimeters. Round your answer to four decimal places.
4 . A machine makes spherical balls. Diameters X are normally distributed with mean 240.0 mm and standard deviation 3.0 mm. Another machine, working independently, makes sockets with diameters Y that are normally distributed with mean 249.0 mm and standard deviation 4.0 mm. A ball will fit into the socket only if ; otherwise the ball is too big for the socket. Define the “gap” to be the difference between the socket diameter and the ball diameter. Therefore a ball...
A manufacturer produces widgets whose lengths are normally distributed with a mean of 9.9 cm and standard deviation of 3.7 cm. A. If a widget is selected at random, what is the probability it is greater than 9.7 cm.? B. What is the standard deviation of the average of samples of size 41 ? C. What is the probability the average of a sample of size 41 is greater than 9.7 cm? Round answer to four decimal places.