How would I approach this problem?
Homework Answers
4Fe3O4 + O2 ----------> 6Fe2O3
according to balanced reaction
4 x 231.53 g Fe3O4 gives 6 x 159.69 g Fe2O3
0.450 g Fe3O4 gives 0.450 x 6 x 159.69 / 4 x 231.53 = 0.466 g Fe2O3
therotical yield = 0.466 g
2) % yield = (actual yield / therotical yield) x 100
25.0 = (actual yield / 0.466) x 100
actual yield / 0.466 = 0.25
actual yield = 0.1165 g
actual yield = 0.1165 g
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How would I approach this problem?
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