Let
A: event of receiving message A
successfully
B: event of receiving message B
successfully
C: event of receiving message C
successfully
Hence compliments of the above events are
A': event of not receiving message A'
successfully
B': event of not receiving message B'
successfully
C': event of not receiving message C'
successfully
Given
P(A) = 0.6
P(B) = 0.7
P(C ) = 0.9
Hence,
P(A') = 1 - P(A) = 1 - 0.6 = 0.4
P(B') = 1 - P(B) = 1 - 0.7 = 0.3
P(C') = 1 - P(C) = 1 - 0.9 = 0.1
7) To find P(successfully receiving no
signals)
= P(A'B'C')
= P(A')*P(B')*P(C')
= 0.4*0.3*0.1
= 0.012
Answer : Option 3
8) To find P(successfully receiving two signals
only)
= P(ABC' OR A'BC OR AB'C)
= P(ABC') + P(A'BC) + P(AB'C)
= 0.6*0.7*0.1 + 0.4*0.7*0.9 + 0.6*0.3*0.9
= 0.456
Answer : Option 2
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