The size of the nucleus is about 10-14 m in diameter. If you wanted to add another proton to a Uranium nucleus (92 protons and 146 neutrons), how strong is the repulsive force at the "edge" of the nucleus?
Size of Uranium nuceus, \(d=10^{-14} \mathrm{~m}\)
Radius of the nucleus, \(r=5 \times 10^{-15} \mathrm{~m}\)
Charge of proton, \(q=1.6 \times 10^{-19} \mathrm{C}\)
Number of protons, \(n=92\) protons
$$ \begin{aligned} \text { Electrostatic force, } F &=\frac{k q_{1} q_{2}}{r^{2}} \\ &=\frac{n k q^{2}}{r^{2}} \\ &=\frac{92 \times 9 \times 10^{9} \times\left(1.6 \times 10^{-19}\right)^{2}}{\left(5 \times 10^{-15}\right)^{2}} \\ &=847.87 \mathrm{~N} \end{aligned} $$
The size of the nucleus is about 10-14 m in diameter. If you wanted to add another proton to a Uranium nucleus (92 protons and 146 neutrons), how strong is the repulsive force at the "edge" of the nucleus?
5) A nucleus of Uranium-238 may be considered to contain 92 positively charged protons and 146 neutrons of the same mass as the protons, but no charge. Assuming that the volume of the nucleus is 238 times that of a proton, and the proton to be a sphere of radius 1.2 x 10^-15m, what is the strength of the electric field at the surface of the nucleus?