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Questions 14-17: For the control system shown below Design the compensator so that the unit-step response...
Q.4 A position control system is shown in Figure Q4. Assume that K(s) = K, the plant 50 s(0.2s +1) transfer function is given by G(s) s02s y(t) r(t) Figure Q4: Feedback control system. (a) Design a l...
Q.4 A position control system is shown in Figure Q4. Assume that K(s) = K, the plant 50 s(0.2s +1) transfer function is given by G(s) s02s y(t) r(t) Figure Q4: Feedback control system. (a) Design a lead compensator so that the closed-loop system satisfies the following specifications (i) The steady-state error to a unit-ramp input is less than 1/200 (ii) The unit-step response has an overshoot of less than 16% Ts +1 Hint: Compensator, Dc(s)=aTs+ 1, wm-T (18 marks)...
Please solve parts (a) and (b) neatly and show problem solving. Ignore reference to part 1, but please still plot the root loci. For the system given in Figure 1 a) Design a PD compensator with the t...
Please solve parts (a) and (b) neatly and show problem solving.
Ignore reference to part 1, but please still plot the root
loci.
For the system given in Figure 1 a) Design a PD compensator with the transfer function: to give a dominant root of the closed-loop characteristic equation of the compen- sated system at s -1+j1 (i.e., a settling time Ts of less than 6 seconds and a maximum overshoot Mo of less than 10%). Required Pre-Practical work] (b)...
% We can couple the design of gain on the root locus with a % step-response...
% We can couple the design of gain on the root locus with a
% step-response simulation for the gain selected. We introduce
the command
% rlocus(G,K), which allows us to specify the range of gain, K,
for plotting the root
% locus. This command will help us smooth the usual root locus
plot by equivalently
% specifying more points via the argument, K. Notice that the
first root locus
% plotted without the argument K is not smooth. We...
4. Referring to the closed-loop system shown as below, design a lead compensator Ge(s) such that...
4. Referring to the closed-loop system shown as below, design a lead compensator Ge(s) such that the phase-margin is 45o, gain margin is not less than 8dB, and the static velocity error constant Ky is 4.0 sec1. Plot unit-step and unit-ramp response curves of the compensated system with MATLAB.
Problem 4. Consider the control system shown below with plant G(s) that has time con- stants...
Problem 4. Consider the control system shown below with plant G(s) that has time con- stants T1 = 2, T2 = 10, and gain k = 0.1. 4 673 +1679+1) (1.) Sketch the pole-zero plot for G(s). Is one of the poles more dominant? Using MATLAB, simulate the step response of the plant itself, along with G1(s) and G2(s) as defined by Gl(s) = and G2(s) = sti + 1 ST2+1 (2.) Design a proportional gain C(s) = K so...
Question three The figure below shows a unit step response of a second order system. From...
Question three The figure below shows a unit step response of a second order system. From the graph of response find: 1- The rise timet, 2- The peak timet, 3- The maximum overshoot Mp 4- The damped natural frequency w 5. The transfer function. Hence find the damping ratio ζ and the natural frequency ah-Find also the transfer function of the system. r 4 02 15 25 35 45 Question Four For the control system shown in the figure below,...
3. Consider the tilt control block diagram shown below R(s) DesiredG(s) 12 s(s+10)(s+70) Y(s) Til...
3. Consider the tilt control block diagram shown below R(s) DesiredG(s) 12 s(s+10)(s+70) Y(s) Tilt tilt Design specifications require an overshoot of less than 5% and a settling time of less than 0.6 seconds. (a) Use MATLAB to sketch the root locus (rlocus command) with a proportional controller and use the root locus to determine a value for K (if any) that will satisfy the design requirements (b) Design a lead compensator Ge(s) to satisfy the design specifications. You can...
Problem 8: A control system for an automatic fluid dispenser is shown below: 125 pointsl Y(s) K6s...
I need the solution using the simulink and if any codes
available please, thanks
Problem 8: A control system for an automatic fluid dispenser is shown below: 125 pointsl Y(s) K6s + 12) Obtain the Closed-loop Transfer Function for the above block diagram. Simulate the system for a unit step input for the following values of K: 15, 30 and 50 On a single graph, plot the response curves for all three cases, for a simulation time of 20 seconds....
1 CONTROL SYSTEM ANALYSIS & DESIGN Spring 2019 HW 7 Due 4/4/2019, Thursday, 11:59pm 1. Design...
1 CONTROL SYSTEM ANALYSIS & DESIGN Spring 2019 HW 7 Due 4/4/2019, Thursday, 11:59pm 1. Design a lead compensator for the closed-loop (CL) system whose open loop transfer function is given below. Design objectives: reduce the time constant by 50% while maintaining the same value of the damping ratio for the dominant poles. Please note that H(s)-1. Please use the method based on root locus plot. G(s) 2 [s(s+2)] Please include detailed step Obtain the location of the desired dominant...
Consider the electro-mechanical feedback control system shown in Figure 3. The voltage Ea(s) - Liea(t)) is...
Consider the electro-mechanical feedback control system shown in Figure 3. The voltage Ea(s) - Liea(t)) is generated by an amplifier whose transfer function is Ga(s) -5 The position sensor has a transfer function H(s) 1 and the pre-compensator transfer function is pot X (s) Ea(s) The "Electro-Mechanical System" block, is X(s) Ea(s) 5.05s3 101s2 +505.2s 100 R(s) Amplifier, |Ea(S)Electro-MechanicalX(S) Controller, Gc(s) K, pot Ga(s) System, G(s) Encoder H(s) Figure 3: Electro-mechanical control system for Question 3 Consider a proportional controller...
Q.4 A position control system is shown in Figure Q4. Assume that K(s) = K, the plant 50 s(0.2s +1) transfer function is given by G(s) s02s y(t) r(t) Figure Q4: Feedback control system. (a) Design a lead compensator so that the closed-loop system satisfies the following specifications (i) The steady-state error to a unit-ramp input is less than 1/200 (ii) The unit-step response has an overshoot of less than 16% Ts +1 Hint: Compensator, Dc(s)=aTs+ 1, wm-T (18 marks)...
Please solve parts (a) and (b) neatly and show problem solving.
Ignore reference to part 1, but please still plot the root
loci.
For the system given in Figure 1 a) Design a PD compensator with the transfer function: to give a dominant root of the closed-loop characteristic equation of the compen- sated system at s -1+j1 (i.e., a settling time Ts of less than 6 seconds and a maximum overshoot Mo of less than 10%). Required Pre-Practical work] (b)...
% We can couple the design of gain on the root locus with a
% step-response simulation for the gain selected. We introduce
the command
% rlocus(G,K), which allows us to specify the range of gain, K,
for plotting the root
% locus. This command will help us smooth the usual root locus
plot by equivalently
% specifying more points via the argument, K. Notice that the
first root locus
% plotted without the argument K is not smooth. We...
4. Referring to the closed-loop system shown as below, design a lead compensator Ge(s) such that the phase-margin is 45o, gain margin is not less than 8dB, and the static velocity error constant Ky is 4.0 sec1. Plot unit-step and unit-ramp response curves of the compensated system with MATLAB.
Problem 4. Consider the control system shown below with plant G(s) that has time con- stants T1 = 2, T2 = 10, and gain k = 0.1. 4 673 +1679+1) (1.) Sketch the pole-zero plot for G(s). Is one of the poles more dominant? Using MATLAB, simulate the step response of the plant itself, along with G1(s) and G2(s) as defined by Gl(s) = and G2(s) = sti + 1 ST2+1 (2.) Design a proportional gain C(s) = K so...
Question three The figure below shows a unit step response of a second order system. From the graph of response find: 1- The rise timet, 2- The peak timet, 3- The maximum overshoot Mp 4- The damped natural frequency w 5. The transfer function. Hence find the damping ratio ζ and the natural frequency ah-Find also the transfer function of the system. r 4 02 15 25 35 45 Question Four For the control system shown in the figure below,...
3. Consider the tilt control block diagram shown below R(s) DesiredG(s) 12 s(s+10)(s+70) Y(s) Tilt tilt Design specifications require an overshoot of less than 5% and a settling time of less than 0.6 seconds. (a) Use MATLAB to sketch the root locus (rlocus command) with a proportional controller and use the root locus to determine a value for K (if any) that will satisfy the design requirements (b) Design a lead compensator Ge(s) to satisfy the design specifications. You can...
I need the solution using the simulink and if any codes
available please, thanks
Problem 8: A control system for an automatic fluid dispenser is shown below: 125 pointsl Y(s) K6s + 12) Obtain the Closed-loop Transfer Function for the above block diagram. Simulate the system for a unit step input for the following values of K: 15, 30 and 50 On a single graph, plot the response curves for all three cases, for a simulation time of 20 seconds....
1 CONTROL SYSTEM ANALYSIS & DESIGN Spring 2019 HW 7 Due 4/4/2019, Thursday, 11:59pm 1. Design a lead compensator for the closed-loop (CL) system whose open loop transfer function is given below. Design objectives: reduce the time constant by 50% while maintaining the same value of the damping ratio for the dominant poles. Please note that H(s)-1. Please use the method based on root locus plot. G(s) 2 [s(s+2)] Please include detailed step Obtain the location of the desired dominant...
Consider the electro-mechanical feedback control system shown in Figure 3. The voltage Ea(s) - Liea(t)) is generated by an amplifier whose transfer function is Ga(s) -5 The position sensor has a transfer function H(s) 1 and the pre-compensator transfer function is pot X (s) Ea(s) The "Electro-Mechanical System" block, is X(s) Ea(s) 5.05s3 101s2 +505.2s 100 R(s) Amplifier, |Ea(S)Electro-MechanicalX(S) Controller, Gc(s) K, pot Ga(s) System, G(s) Encoder H(s) Figure 3: Electro-mechanical control system for Question 3 Consider a proportional controller...
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