1.
13.2 kg = 13200 gm
molar mass of C3H8 = 44.1 gm/mole
According to reaction 1 mole of
C3H8
Hrxn =
-2044 KJ
that mean for 44.1 gm C3H8
Hrxn =
-2044 KJ
then for 13200 gm of C3H8
Hrxn =
-2044 X 13200 / 44.1 = -611809.5 KJ
if 13.2 Kg C3H8 completly
combusted then
Hrxn =
-611809.5 KJ
If 13.2 kg C3He is completely combusted, what is AHan? 2. Find dHnn for C (s)...
Part A Calculate Δ Han for the following reaction: C(s) +H2O(g)CO(g)+H2() Use the following reactions and given ΔΗ values: C(s) + O2 (g)- CO2 (g), ΔΗ-393.5 kJ 2CO (g) + O2 (g)--2CO2 (g), ΔΗ-566.0 kJ 2H2 (g) +02 (g)-2H3O(g). Ан :-483.6 kJ Express your answer using four significant figures. kJ Submit Request Answer
Find ∆H◦ of the reaction 2C2H2(g) + 5O2(g) = 4CO2(g) + 2H2O(g), as it is written, given the following: 2C(s) + H2(g) = C2H2(g), ∆H◦ = +227.4 kJ, 2H2(g) + O2(g) = 2H2O(g), ∆H◦ = −483.6 kJ, C(s) + O2(g) = CO2(g), ∆H◦ = −393.5 kJ.
C(s) + O2(g) + CO2(g) AH° = -393.5 kJ (5 pts) Given the following enthalpy values for reactions at 25°C, what is AH at 25°C for the following reaction: C3H3(g) + 502(g) + 4H2O(g) + 3CO2(g) AH = -2043 kJ 3C(s) + 4 H2(g) → C3H8 (g) 2H2(g) + O2(g) + 2H2O(g) AH° = -483.6 kJ
8. Find ∆H◦ of the reaction 2C2H6(g) + 7O2(g) = 4CO2(g) + 6H2O(g), as it is written, given the following: 2C(s) + 3H2(g) = C2H6(g), ∆H◦ = −84.68 kJ, 2H2(g) + O2(g) = 2H2O(g), ∆H◦ = −483.6 kJ, C(s) + O2(g) = CO2(g), ∆H◦ = −393.5 kJ. (A) −3194 kJ (B) −3109 kJ (C) −2940 kJ (D) −2855 kJ (E) −1428 kJ
Consider the following data. 2 C(s) + H2(g) C2H2(g) H = +226.8 kJ CO2(g) C(s) + O2(g) H = +393.5 kJ 2 H2O(l) 2 H2(g) + O2(g) H = +571.7 kJ Use Hess's law to calculate H for the reaction below. 2 C2H2(g) + 5 O2(g) 4 CO2(g) + 2 H2O(l) find kJ
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g) Given: C (s) + O2 (g) --> CO2 ΔH = -393 kJ H2 + 1⁄2O2 --> H2O. ΔH = -286 kJ CH4 + 2O2 --> CO2 + 2H2O ΔH = -892 kJ
Consider the following data.
CH4(g) C(s) + 2 H2(g)
H = +74.8 kJ
C(s) + O2(g)
CO2(g)
H = -393.5 kJ
2 H2(g) +
O2(g) 2 H2O(l)
H = -571.7 kJ
Use Hess's law to calculate H for the reaction below.
CH4(g) + 2 O2(g) CO2(g) + 2 H2O(l)
H = _____ kJ
Calculate ΔHrxn for the following reaction: 5 C (s) + 6 H2 (g) → C5H12 (l) Use the following reactions and given ΔH′s. C5H12 (l) + 8 O2 (g) → 5 CO2 (g) + 6 H2O (g), ΔH= -3244.8 kJ C (s) + O2 (g) → CO2 (g), ΔH= -393.5 kJ 2 H2 (g) + O2 (g) → 2 H2O (g), ΔH = -483.5 kJ
Question 6 1.5 pts Predict under what temperatures (all temperatures, low temperatures, or high temperatures), if any, the following reactions will be spontaneous. A. 2CO(g) + O2(g) = 2002(g), AH rxn=-566.0 kJ [ Select] B. 2NO2(g)2NO(g)+O2(g), AH rxn= +113.1 kJ [ Select ] C. 2H2(g)+O2(g)—2H2O(g), AH rxn=-483.6 kJ [ Select] D. 2H2O2(1)→2H2O(1)+O2(g), AH rxn= -196.0 kJ [Select ]