Question

Write a C++ function that prints an array, skipping over a number of elements. Use the following header:

void printArraySkip(int array[], int elems, int skip) {
}

Where 'array' is an input array of 'elem' integer elements, and 'skip' is the number of elements to skip over. For example, if the function is called like this:

int array[6] = { 5, 7, 11, 12, 18, 19 };
printArraySkip(array, 6, 2);

The output would be:

11 19

in c++. Thanks

Answer 1

#include <iostream>
#include <iomanip>
#include <string>

using namespace std;

void printArraySkip(int array[], int elems, int skip) {
    for (int i = skip; i < elems; i++) {
        cout << array[i] << " ";
        i += skip;
    }
    cout << endl;
}

int main() {
    int array[6] = {5, 7, 11, 12, 18, 19};
    printArraySkip(array, 6, 2);
    return 0;
}

11 19 Process finished with exit code O