レ 8 4. In the mobile in equilibrium, the mass of fish B is 75 g....

Question

Question

science physics

Answer 1

Answer #1

This sysy is in equilibrium.

And Torque = rxF

Now equilibrium equation

15*T = 5*mB

T = 5*75/15 = 25 g

Now total mass at right side = 75 + 25 = 100 g

equilibrium equation

30*mA = 7.5*100 g

mA = 25 g

Mass of fish A = 25 g

Answer 2

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