Question

Points A and B are separated by a lake. To find the distance between them, a surveyor locates a point C on land such than ZCAB = 54.9°. Find the distance across the lake from A to B. 526 yd 54.90 368 yd NOTE: The triangle is NOT drawn to scale. distance = yd Enter your answer as a number; your answer should be accurate to 2 decimal places.

Answer 1

i Sabay 6 64.00 Guin trangle ABC [LAB = 54.90 CA 2368 Yd BC – 526yd akang sama C 368 Yd I wsing law of sires simt - social 7 sin A sin Basin 54.9 sin B a 526 368 Sn 8 = 368 X Am(St 1) 526 . SinB = 0.572393719 B = sin! (0.572393719) TB E 34.92 0 from AABC, the sum of angles is 180 (A + LB + LC = 180° 54.90+ 34,92°+ LC = 188 LC - 180 – 89.82° TLC = 90.189

sin A c = axsenc 526x sin Gooigo) sina sin (54.900 [~ 642.91] distance across the lake from A to B is 642.91 yards 1 The