Question

A football game customarily begins with a coin toss to determine who kicks off the referee toss a coin up with an initial velocity of 5.00 m/s.

what is the total time the coin is in the air before returning to the release point?

A seciban game customary long game customerwy begins with a con 1030 to devermine wine 3 ORP. The reverse es the sain up with an ima vexacity of 5.0 m/s. A HS high does the coin gpakove the point of sease Gede 12 = 1 + 2ax 25 X U2 5looms 3.00+ 2(+93) 19.6 Uromis 25 = 219,8 1275 m - --> 1.28m act b How long does it take for the con to reach a maximum hegna! US - 0.510 st. usloomis b = 5.00 + (+98) uto 5.00 Giveni 9.8 c) What is the total time the coin is in the air berate returning to its release point? Given: ULS.9 m/s UF = Omis a +9.8

Answer 1

(c) During the time the coin travels upward, gravity causes its speed to decrease to zero. On the way down, however, gravity causes the coin to regain the lost speed.

Thus, the time for the coin to go up is equal to the time for it to come down. In other words, the total travel time is twice the time for the upward motion.

We can use the equation for finding the - upward travel f time o - t = v- vo - o - 5 m/s - 9.8m/s² . 0.510 sec & twice this The total up and down time is value , :. t= 2 (0.510) t = 1.02 sec An