Homework Answers
net displacement in x-direction = d1 cos(theta1) - d2 cos(theta2-theta1) - d3 cos(theta3+theta2-theta1) = -1.103 m
net displacement in y-direcion = d1 sin(theta1) + d2 sin(theta2-theta1) - d3 sin(theta3+theta2-theta1) = -6.5815 m
magnitude of displacement = sqrt( (-1.103)^2 + (6.5815)^2 ) = 6.6733 m
angle of displacement = arctan(-6.5815/-1.103) = -100.3444 degrees
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The figure shows the path taken
by a drunk skunk over level ground, from initial point i to final
point f. The angles are θ1 = 31.0°, θ2 = 52.0°, and θ3 = 77.0°, and
the distances are d1 = 5.70 m, d2 = 8.80 m, and d3 = 14.0 m. What
are the (a) magnitude and (b) angle of the skunk's displacement
from i to f? Give the angle as a positive (counterclockwise) or
negative (clockwise) angle of magnitude...
1. A figure skater glides along a circular path of radius
5.28m.
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magnitude of the displacement vector. (SI unit: m)
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distance she skated. (SI unit: m)
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