Given,
Temperature of cold reservoir, Tc = -70
C
= (273.15 + (-70))
= 203.15 K
Temperature of hot reservoir, Th = 250
C
= (273.15 +250)
= 523.15 K
Now,
efficiency,
= (1 - (Tc/Th))*100
= (1 - (203.15 / 523.15))*100
= (1 - 0.39)*100 = 0.61*100
= 61%
Now,
Work done, W = 500 MJ
Let heat provided be QH
Now,
efficiency,
= W / QH
=> 0.61 = 500 * 106 / QH
=> QH = (500 * 106) / 0.61
= 819.67 * 106
1 kWh = 3.6 * 106 J
thus,
QH = (819.67 * 106 / 3.6 * 106 ) kWh
= 227.69 kWh
4. The nighttime temperature on Mars during its Summertime can be as low as -70.0°C. A....
A Carnot engine whose low-temperature reservoir is at 18.0°C has an efficiency of 21.9%. By how much should the Celsius temperature of the high-temperature reservoir be increased to increase the efficiency to 57.7%?
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A
Carnot engine has an efficiency of 45 % and takes in heat from a
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What is the Celsius temperature of the engine's
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T = _____ °C
(Answer is NOT 168°C)
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step by step explanation please
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please make sure it’s in celcius degrees not degrees celcius or
kelvins
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