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Problems for Week 9: Problem 4 Previous Problem Problem List Next Problem (2 points) Compute the surface area of revolution o
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246 $ 10 $ 1+/dy 2 J (dx) doc 4 4x+3 dy = 4 da [ 1442 = 1+ 16 = /17 (J17) dx S = 21 17 4x +3 da s = 2T J17 cs Scanned with Ca

ड. ग17 ( 2 2 + 32x) SE ITDA ( 2 (5) + 3(5) - 2 (५) -3 (५) 5: IT JI ( 50 + 15 - 32 -12) S: 2117 (21) S = 42717 Scanned with Ca

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