Question

For a parallelle capacitor with capacitance and Voltage rating to decrease the voltage rating to half as much and retain the capacitance the amount of electric material needed to as much ОА OC reduce toate as much

Answer 1

q) given parallel plate capacitor capacitance=c voltage ratuga vanane required voltage rating a man 2 Capacitance=c amount of dielectric material Cc+. we know scien we know man (= Capacitance Q=chaye V voltage rating A = area of each plate d=distance between each plate E=to lib air is used as . dielectric material]

E = to fr lits any other dielectric material is used to = 8-8581612 flm ( constant] Eral air Ev>l for other diclectic material we know c ę [previous epocitance] we have to reduce voltage rating by half. c'= Q c'a new capacitance c=2Q - Vnan (=2c) y but we should not in Question it has should retain same - therefore we should parameters, but in to change dielectic change "C" because given that it opacitance. change other question he arked material Ev.

C: Co by A [before] if we take Ev=2 c'= to (2 E) A [ After choping ! de dretechic metemel هم 2 دا Result: The amount of dielectric material needed should increase to twice as much [option "C"]. - In short mannes if we want to reduce voltage rating half without Charrire capacitance then by increasing the dielectric material to twice obtain solution. (26r] we