Water at a pressure of 3.30 atm at street level flows into an
office building at a speed of 0.70 m/s through a pipe 6.40 cm in
diameter. The pipes taper down to 2.40 cm in diameter by the top
floor, 28.0 m above. Calculate the water pressure in such a pipe on
the top floor.
Your submitted answer is : 36289.7
Pa
Given:
gauge pressure p1 = 3.30 atm (1 atm = 1.05*10^5 pascal)
= 3.30*1.05*10^5
= 3.46*10^5 pascal
speed v1 = 0.70 m/s
diameter of the pipe d1 = 6.4*10^-2 m
diameter of the pipe d2 = 2.4*10^-2 m
height of the pipe h = 28 m
From Bernoulli's equation of fluids
p2 = P1+ρgh
where ρ is the density of the water
p2 = 3.46*10^5+(0.9*10^3*9.8*28)
= 5.93*10^5 pascal
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