Question

the question, this is not running it throws an exception would you help me it is a java program

// why this is not running would you help me
public class sample
{
    public static void main(String[] args){
        String str[][] = new String[10]['K'];
       
        for(int i= 1;i<=10; i++){
            for(char j= 'A';j<='J'; j++){
                System.out.print(i +" "+ j);
                 str[i][j] = "A";
                  System.out.print(" ");
                 
                   
            }
             System.out.println();
            
           
        }
       
    }

}

Answer 1

The exception you got is Array index out of bound of Exception: This exception occurs when you are trying to access any element which is not in the array memory

The index of array starts from 0. That is Array[9] will index to 10th element. In your program you are trying to access 11th element which is not there in the array. hence throwing exception.

Updated program with output:

public class Base1 {

      public static void main(String[] args) {

            //Changes made in here String Declaration as

            //new String [11]['K]

            String str[][] = new String[11]['K'];

            //Without changing the string declaration we can get the same output

            //by changing the next line as "for(int i= 0;i<10; i++){"

            for(int i= 1;i<=10; i++){

                  for(char j= 'A';j<='J'; j++){

                        System.out.print(i +" "+ j);

                        str[i][j] = "A";

                        System.out.print(" ");

                        }

                  System.out.println();

              }

      }

}

Output: