Homework Answers
Ans: ‘a’
Octane = C8H18
Mass of octane taken = 0.450 kg = 450 g
Molar mass of octane = 114.23 g/mol
No. of moles of octane taken = 450/114.23 = 3.939 mol
Combustion reaction: 2 C8H18 + 25 O2 ---> 16 CO2 + 18 H2O
2 moles of octane give 16 moles of CO2. 3.939 moles of octane is expected to give 31.512 moles of CO2.
Molar mass of CO2 = 44.01 g/mol
Mass of 31.512 moles of CO2 = 31.512 x 44.01 = 1386.8 g (Theoretical yield)
Mass of CO2 formed = 1.25 kg = 1250 g (experimental yield)
% yield = (experimental yield/theoretical yield)x100 = (1250/1386.8) x 100 = 90.136
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