Question

WRITE A PROGRAM IN C THAT DOES THE FOLLOWING:

The numbers are real numbers, read in as double precision floating-point numbers, one number perline, possibly with some white space before or after. Hint: use scanf. There are guaranteed to be no more than one million (that’s 10^6) numbers in the input, and no fewer than two legitimate numbers. Any number that is equal to zero should be ignored (discarded, not stored in the array or counted in any way).

Answer 1

#include <stdio.h>

int main()
{
//array declaration
double arr[1000000], temp;
  
//display message
//enter 10 times 9 for exit
printf("Enter an array of real numbers (enter 9999999999 for exit): \n");
  
//input array element
for(long i = 0; i < 1000000; i++)
{
//input element
scanf("%lf",&temp);
  
//check if exit code
if(i > 1 && temp == 9999999999)
{
//break statement
break;
}
  
//ignore the zero
if(temp != 0)
{
arr[i] = temp;
}
else
{
i--;
}
}
return 0;
}

INPUT:

Enter an array of real numbers (enter 9999999999 for exit): 10.50 20.25 30.00 10.90 30.20