We have following information
Length of (cylndrical) tibia; l = 36 cm = 0.36 m
Dia of (cylndrical) tibia; d = 1.4 cm = 0.014 m
Radius of tibia ; r = d/2 = 0.007 m
We need following more information to calculate Shortening in Tibia (Strain). You may use the final derived formula to get the value in number.
a. m= Mass of your body (You can use you mass in kg)
b. Y = Young's modulus of bone (As per question, please use Appendix B to refer it) in N/m2
If Y is in different unit, you may use below conversion rates:
1 pascal (1Pa) = 1 N/m2= 1.450377×10−4 psi ;
1 Giga Pa = 109 N/m2
Now, based on above information we can have following values
Force on tibia; F = m*g; where m is mass of your body
Stress on Tibia;σ = F/ (cross section area) = F/ (π * r2) = F / (π * d2 /4)
If we denote Strain with "x"
Young's modulus of bone, Y = Stress/Strain =σ/x = F / (π * d2 /4) / x
Strain; x = F / (π * d2 /4) /Y = m*g / (π * d2 /4) /Y
Now, Strain is calculated by Ratio of Change in length & Original length
SO, Change in length = Strain * Length of tibia
= x * l
= m*g / (π * d2 /4) /Y *l (unit in meter)
(Please use values in SI unit, m = mass in kg, g = 9.8m/s2, d = 0.014m, l = 0.36m, Y in N/m2 )
2. (10) Model your tibia as a long cylindrical bone; measure its approximate length and estimate...