Question

a. What is the theoretical yield of oxygen if 125 g of H2O2 is decomposed? (10 points) 25+ Imol = 3.67 x 2mol on 134.01 = 3.67 2.0 = zmol H2O2 Imol What is the percent yield if 27.4 grams of O2 are collected? (10 points)

Answer 1

Decomposition of H2O2 is given by the son: н, о, —ң,0 + зо, OR 2 ,0. — 2ң,0 + 10, 2 mel From the reaction it - 2 mol of H₂O2 is clear that: decompases to give I mor of a 2X1+16ҳ2 = 34 3 we know Imot. № 49, Molecular mass • ңо, . 2 ms o, н, °, = 34х2 = 6% / I mo9 = 10х2 = 32 8м OR we can say, 6x3 4ң,9, dormрак, + Qe 32 a bo, и 18 не, .строк, + < 3 зо, Given mass of H ₂ 2 = 125g .: 1254 , но, letovра + доvе = 3 x 12-5 o 4 о, = 58 - 38 4°, Then, theoretical Yield of O₂ = 58.89

Formula to find Percent yield is : olo Yield - = Actual Yield x Theoretical Yield loo Gieven Actual Yield = 27.4g ob O Theoretical Yield = 58.8g = l Yield = 27.4 x Xloo 58.8 = 46.6olo [Percent yield = 46.6%) * Tercent Yiud