Question

A plot of volume vs time, on semi-log graph paper, produced a slope of 14.2 +0.2s-1 and an intercept of 0.011+0.002 m 3. What is the final form of the exponential equation that relates these variables? Select one: O a. V=(0.011+0.002m3)e(14.2+0.25-1)t ob. t=(0.011+0.002m3)e(14.2+0.25-1)V O c. t=(14.20.25-1)e(0.011=0.002m3)V O d. V=(14.240.25-11e(0.011+0.002m3)t

Answer 1

m = slope = 14.2 $\pm$ 0.2 s^-1

logm = log(14.2 $\pm$ 0.2 )

c = intercept = 0.011$\pm$0.002 m³

V = volume = y-axis

t = time = x-axis

we know that

y = mx + c

V = m t + c

for option a)

taking log both side , we get

logV = log(0.011$\pm$0.002) + (14.2 $\pm$ 0.2) t

logV = logc + m t

hence choice a)