Question

Ideally, the van't Hoff factor, i, can be determined by the following equation [i = moles of particles/moles of dissolved solute] What I the van't Hoff factor for BeCl_2? 1 2 3 4

Answer 1

1 mole of $BeCl_2$ on complete dissociation will give 3 moles of particles.

$BeCl_2 \rightarrow Be^{2+} + 2Cl^-$

The van't Hoff factor $i = \dfrac { \text { moles of particles} }{ \text { moles of dissolved solute} } = \dfrac {3}{1} = 3$

Hence, the option (C) is the answer.