Answer:------------
Given,
Expression, X = (A - B * C) + ( D + E) * F
Postfix Notation of given Expression,
==> ( A - B C* ) + ( D E + ) * F
==> (A B C * - ) + ( D E + F * )
==> A B C * - D E + F * +
Here, TOS = Top of Stack
| 0 Address | 3 Address |
| PUSH A (TOS <- A ) | MUL R1, B,C ( R1 <- B * C ) |
| PUSH B (TOS <- B ) | SUB R2, A, R1 (R2 <- A - R1) |
| PUSH C (TOS <- C ) | ADD R3 ,D ,E (R3 <- D + E ) |
| MUL (TOS <- B * C ) | MUL R3,R3,F (R3 <- R3 * F ) |
| SUB (TOS <- A - B * C ) | ADD X, R2, R3 ( X <- R2 + R3 ) |
| PUSH B (TOS <- D ) | |
| PUSH B (TOS <- E ) | |
| ADD (TOS <- D + E ) | |
| PUSH F (TOS <- F ) | |
| MUL (TOS <- (D + E ) * F ) | |
| ADD (TOS <- ( A - B * C ) + (D + E ) * F ) ) | |
| POP X ( X <- TOS ) |
6 pts) Compare zero- and three-address machines by writing programs to compute X = (A-B *...
Program the following advanced language formulas using the
universal command statement expression method for the 0, 1, 2, 3
address machine in Figure 1. However, use any register name you
want to use.
A = (A + B * C) / (D – B * E)
0 Address PUSH M POPM ADD SUB MUL DIV 1 Address LOADM STOREM ADDM SUBM MUL M 2 Address MOVE ( XY) ADD (X-X+Y) SUB (X--X-Y) MUL (X--XXY) DIV ( XXY) 3 Address MOVE...
Note: The question needs to be answered in "C
Programming Languange ". And after the question find 3 pages for
needed informations.
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