A force F, with components Fx = 3 N, Fy = 9N, and Fx = 3 N acts on a particle located at r, with components rx = 6 m. ry = 3 m, and rz = 3 m.
What is the magnitude of the torque about the origin due to this force?
Do not include units. Round your answer to the nearest whole number.
Torque Magnitude = __Nm
A force F, with components Fx = 3 N, Fy = 9N, and Fx = 3 N acts on a particle located at r
Force F = (-5.3 N) ? + (3.2 N); acts on a particle with position vector 7 = (2.4 m) î + (3.9 m)). what are (a) the magnitude of the torque on the particle about the origin and (b) the angle between the directions of 7 and 7 (a) Number Units (b) Number Units
1) Force F =(-8.00 N){+(6.00 N) j acts on a particle with position vector r = (3.00 m)i +(4.00 m)j. What are (a) the torque on the particle about the origin, in unit-vector notation, and (b) the angle between the directions of r and F?
please help and show work
010 (part 1 of 3) 10.0 point:s A force F-Fx + Fy J +F~ k acts on a particle located at X - (r,y, z). Given x -1.92 m. y 8.25 m and -1.12 m. calculate the three components of the torque First, calculate the Ta component Answer in units ofNm 011 (part 2 of 3) 10.0 points Second, calculate the Ty component. Answer in units of Nnm. 012 (part 3 of 3) 10.0 point:s...
A particle moves through an xyz coordinate system while a force
acts on the particle. When the particle has the position vector
r
= (2.00 m) - (3.00 m) + (2.00 m) , the force is F
= Fx + (7.00 N) - (6.00 N) , and the corresponding torque about the
origin is T
= (4.00 N·m) + (10.0 N·m) + (11.0 N·m) . Determine Fx.
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A particle is located on the x axis 4.9 m from the origin. A force of 38 N, directed 30° above the x axis in the x-y plane, acts on the particle. What is the torque about the origin on the particle? Round your answer to the nearest whole number. Use a minus sign to indicate a negative direction and no sign to indicate a positive direction.
A particle is located on the x axis 3.1 m from the origin. A force of 39 N, directed 30° above the x axis in the x-y plane, acts on the particle. What is the torque about the origin on the particle? Round your answer to the nearest whole number. Use a minus sign to indicate a negative direction and no sign to indicate a positive direction. Please show work! Thank you!
A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r Overscript right-arrow EndScripts = (2.00 m) i Overscript ̂ EndScripts - (3.00 m) j Overscript ̂ EndScripts + (2.00 m) k Overscript ̂ EndScripts, the force is Upper F Overscript right-arrow EndScripts = Fx i Overscript ̂ EndScripts + (7.00 N) j Overscript ̂ EndScripts - (6.00 N) k Overscript ̂ EndScripts, and the corresponding torque about...
A force F = 61 N i acts on an object
at a point (x0, y0) = (6.2 m, 4.7
m) as shown in the figure. What is the magnitude of the
torque generated by this force about the origin?
What is the magnitude of the torque generated by this force
about the point (x, y) = (2.9 m, 1.6 m)?
Suppose the object is free to rotate about the z axis. If the
object has a moment of inertia...
force Fx acts on a particle that has a mass of 2 kg. The force is related to the position x of the particle by the formula F 3, where C-0.5 if x is in meters and Fy is in Newton (a)What are the SI units of C? (Use the following as necessary: N and m.) (b) Find the work Wdone by this force as the partidle moves from x - 2.8 m to x - 1.6 m (C) At...
007 (part 1 of 2) 10.0 points A force F Fo i + Fy j acts on a particle that undergoes a displacement of S + sy where F: = 2 N, Fy =-5 N, sx = 4 m, and sy 3 m. Find the work done by the force on the particle. Answer in units of J 008 (part 2 of 2) 10.0 points Find the angle between F and S. Answer in units of o