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9. Suppose A = 12 and B=5. What is the value of 8 + A + 2B = 10. A rectangle has a base (width) of 12 and a height of 4. What

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Answer #1

9) 8 + A + 2B = 8 + 12 + 2(5)

= 30

10) Area of rectangle = 12\times4

= 48

11) Y = 30 + 3X

when X = 0

Y = 30 + 3(0)

= 30

When X = 5  

Y = 30 + 3(5)

= 45

when X = 10  

Y = 30 + 3(10)

= 60

12) at Q = 4 ATC = 8

13) at Q = 3 MC = 11

14) Where MC and ATC curves intersect to each other MC = ATC

So at Q = 2 MC = ATC = 4

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