Question

An electron is moving with a velocity of 2.56x10' m/s. Calculate the minimum possible uncertainty in its position. (a) 0.038x101 m c (b) 4.50 x10-10 m (c) 4.50 x101 m (d) None of the above

Answer 1

Given that rightarrow An electron is moving with a velocity of 2.56 times 10^7 m/s the minimum possible uncertainty in its position is: delta V = 2.56 times 10^7 M/s h = 6.63 times 10^-34 m = 9.1 times 10^-31constants. The uncertainty in position can be given by delta x = [h/ n pi times 1/ m delta v] = 6.63 times 10^-34/4 times 3.14 times 1/ 9.1 times 10^-31 times 2.56 times 10^7 = 6.63 times 10^-3/12.56 times 10^-7/232.96 = 6.63/292.59 times 10^-10 = 0.0226 times 10^-10 = 2.26 times 10^-12 m the correct option is Ld)non of the above.