Question

You generate a standing wave on a 1-m long string, fixed on both ends, by forcing it to vibrate at 100 Hz. When doing so, the standing wave has a wavelength of 1 m. According to the wave equation, v=Af, the speed of the wave along the string is 100 m/s. Suppose the forcing frequency is doubled to 200 Hz, without changing the length, tension or ends of the string. What is the new wavelength and wave speed? A. The same as before, 1 m and 100 m/s B. The wavelength is 0.5 m (half of what it was) and the wave speed is 200 m/s (twice what it was) C. The wavelength is 0.5 m (half of what it was) and the wave speed is 100 m/s (the same as before) D. The wavelength is 1 m (the same as before) and the wave speed is 200 m/s (twice what it was) E. The wavelength is 0.75 m (3/4 of what it was before) and the wave speed is 133 m/s (4/3 times what it was before)

Answer 1

tension -Wave speed is fixed if the length and in string is unchanged. Given di = 1m f= 100 HZ *2= ? fa= 200 HZ So, as v = V2 or, x, fi = Azfa or = xifi _ 1x100 - m - 0.5m 200 So, wavelength Comment obtion: c wave speed is 0.5m and velocity is unchanged please put a thumb (100 m/s) up