Question

Based

Initial concentrations (M)
Mixture	[XY]	[X]	[Y]
A	0.100	0	0
B	0.500	0.100	0.100
C	0.200	0.300	0.300

Part B: Based on a Kc value of 0.150 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively?

Part C: Based on a Kc value of 0.150 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively?

Please show work and make sure it's correct

Answer 1

A) The ICE table constructed is as follows Initial (M) Change (M) Equilibrium (M): 0.100 0.100-x x)[T] XY Equilibrium constant, Kc - 0.150 = 0100-x x = 0.0686 According to the ICE table Equilibrium concentration of X, = (x) M = 0.0686M Equilibrium concentration of Y, [Y] -(x) M0.0686M Equilibrium concentration of XY, [XY]- (0. 100-x) M (0.100-00686)M= 0.0314M

B) The ICE table constructed is as follows: Initial (M) Change (M) Equilibrium (14): 0.500 0.100 0.100 0.500-x 0.100+x 0.100+ x Equilibrium constant, K XY 0.100+x (0.500-x) 0.150 x 0.134 According to the ICE table Equilibrium concentration of X, [X] (0.100+x) M Equilibrium concentration of Y, [Y] = (0.100 + x) M Equilibrium concentration of XY, XY-(0.500-x) M (0.100+0 134) M 0 234 M (0.100+0.134) M0.234 M (0500-0 134)M 0 366 M C) The ICE table constructed is as follows: XY(g) 0.200 X() + Y(g) 0.300 Initi al (M) Change (M) Equilibrium (M): 0.300 0.200+x 0.300-x 0.300-r Equilibrium constant, K,= XY 0.150200+) (0.300-)2 x=0.09 10 According to the ICE table Equilibrium concentration of X, [x]- (0.300-x) M (0.300-0.0910)M 0.209 M Equilibrium concentration of Y, [Y]-(0.300-x) M (0.300-00910)M 0.209 M Equilibrium concentration of XY, [XY] (0.0.200+x) M (0.200+00910)M 0.291M =